Re: RE: Re: Generally accepted good winding technique?
Thanks Kang & Bill.
I see where I got mixed up on the Max torque formula.
Using Kang's 5/99 example, the adjustment for Max turns is simple. Just multiply the calculated Max turns by 1.07. Even I can figure that one out!
How do you calculate the adjusted Max. Torque for 5/99? I assume it is not a simple linear relationship.
Gary H
-----Original Message-----
From: William Gowen <wdgowen_at_gmail.com>
To: Indoor_Construction <Indoor_Construction_at_yahoogroups.com>
Sent: Tue, Oct 8, 2013 12:30 pm
Subject: Re: [Indoor_Construction] RE: Re: Generally accepted good winding technique?
Those are also the formulas I use.
On 10/8/2013 12:42 PM, ykleetx_at_gmail.com wrote:
The formulas I use:
max turns = motor_length * 45.67*SQRT (motor_length / motor_weight )
max torque =( motor_weight / motor_length / 0.11)^1.5
These are used only as guidelines as different batches behave differently.
For my 7/99, the max turns is very accurate. For my 5/99, I can get a 7% more turns.
---In Indoor_Construction_at_yahoogroups.com, <indoor_construction_at_yahoogroups.com> wrote:
Bill,
I think the formula you are using for Max Torque is:
Max Torque =((motor weight in grams/0.11)^1.5)
Am I correct? What formula are you using for Max turns?
Thanks,
Gary H
-----Original Message-----
From: wdgowen <wdgowen_at_...>
To: Indoor_Construction <Indoor_Construction_at_yahoogroups.com>
Sent: Fri, Oct 4, 2013 2:36 pm
Subject: [Indoor_Construction] RE: Re: Generally accepted good winding technique?
For 2 grams(net) x 20" the formulas I use show 2880 turns max and .87 in-oz max.
Received on Tue Oct 08 2013 - 15:59:00 CEST
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