Hi Gary.
It is a lot easier done than said honestly.
You do need a micrometer. Ray Harlan's with the spring removed is accurate enough. And you need a digital scale, preferably with a cup to hold the rubber easily. A ruler. The spreadsheet (or paper/pencil/calculator with formula handy).
Measure and cut strip. Measure width. Measure weight. Plug in the values to get the desired width.
Reach over grab rubber stripper. Cut a bit of test rubber (i.e. super sport. Adjust the cutters to cut to approximate width, should be on right side of rubber with an Oppegard. Feed and cut short section and measure. Adjust as needed until you get the right width. Toss this test stuff.
Now feed in your good rubber and strip away.
Make up a motor to verify.
If all is well, make up a couple more motors if needed.
Regards.
Mike Kirda
--- In Indoor_Construction_at_yahoogroups.com, Warthodson@... wrote:
>
>
> Bill, Mike or anyone,
> But the catch-22 is that first you must accurately measure the width of the strip, then accurately set your slicer to cut a specific width in order to end up with a specific weight loop!
> For the sake of this discussion, assume there is no max. motor weight requirement & you wanted a loop weight of 1 gram, what tolerance would you consider acceptable?
> How many test cuts do you usually need when trying to cut a new width strip? I would say it typically takes me at least 3 short test strips.
> Gary H
>
>
> From: William Gowen wdgowen_at_...
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>
>
>
>
> So you calculate the density of your 1/8" rubber and then calculate the strip width based on the density. I rest my case.
>
>
> On 9/17/2013 10:50 AM, mkirda_at_... wrote:
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>
>
> Here is an example for F1L.
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> Find the loop length that you want. Cut a bit of rubber to be the length plus 2 inches.
>
> i.e. 14" loop, cut (14+1)*2 = 30 inch length = 15" doubled.
>
> Measure the width of the rubber with micrometer - i.e. 0.128"
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> Weigh the length of rubber. i.e. 2.54 grams.
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> You decide you want the rubber to weight 1 gram exactly.
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> Here is the math:
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> 1/2.54 * (15/14) * 0.128 = .05399
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> Strip it to 0.054" and you when you tie off a 14" loop it should be precisely 1 gram.
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> I set up the spreadsheet to have only 1" additional length, but the math above is the same.
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> If anyone has problems with this, I will define variables and post the math that way.
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> Regards.
>
> Mike Kirda
>
Received on Tue Sep 17 2013 - 10:54:32 CEST
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