Re: Re: Helicopter and FF Help

From: Mark Schaefer <SandySchaefer708_at_msn.com>
Date: Sun, 25 Mar 2012 00:11:37 -0400

Your rubber conditioning is fine. Doing it the day before and then the day of use is little better. Trying to get official fight on third or more time the motor is used on copter flight is the best because The motor will take more winds then.

 Before changing the length or diameter of motor based on turns left over at end of flight you need to estimate ultimate time a copter will fly. Then determine how many turns that goal will take, the rest is math. My guess is around 3 minutes which would mean the weight and length are not ready to be adjusted at this time.

 In very general terms 1. are you getting all winds into the motor it will take and can you estimate how many turns this particular will take in a educated manner? 2. Are there any warps in construction, is every part of copter PERFECTLY STRAIGHT, is any wood bending under stress of the motor or during flight? In my experience number two is what needs worked on for higher flight times followed by ONE which is sort of a art in part.

Mark Schaefer

 
 




On Mar 24, 2012, at 11:25 PM, "Kody P." <pipercub0749_at_gmail.com> wrote:

> >Thanks Joshua for responding!
> >
> >I'm getting times around 1:45 with about 1.4g of .125" rubber or 1.86g
> >of .155" rubber. In the first case I am left with a good amount of
> >winds; in the second I am left with almost none. How many winds left is
> >ideal?
> >
> >Do you have any advice for breaking in or prestretching rotors? (#2 on
> >my last message)
> >
> >-Chris
>
> Chris,
>
> I managed a flight of 1:39 today with a 2g loop of .125". I know that I need to shorten this motor, as I'm landing with a whopping 47% of my original winds.
>
> My break-in technique is a mishmash of several techniques. First, I stretch the rubber six times its length and lubricate it. I leave it for six minutes in the stretched position. I tie the rubber with the O-rings, extensions, ect. and wind it up slowly to about 75% of its maximum torque. I would also appreciate some advice to refine this method.
>
> -Kody
>
>
Received on Sat Mar 24 2012 - 21:11:04 CET

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