--- In Indoor_Construction_at_yahoogroups.com, "stankimel"
<stankimel_at_...> wrote:
>
> --- In Indoor_Construction_at_yahoogroups.com, "Erich Reinbolz"
> <erich44_at_> wrote:
> >
> > Making the prop for a Cezar Banks PP. On a 12" dia. prop and 22"
> > pitch, what angle would the blade be? Not sure how this pitch
stuff
> > works. Would seem to me it would be easier just to state the blade
> > angle, in the plans. Am sure I am missing something here. What it
is I
> > do not know. Need some help, please.
> >
> > erich
> >
>
> You can find any of the variables with p=c(tan0),where p=pitch in
> inches, c=the circumference of the circle that would made by a
> revolution of the prop at the radius in question. 0=the angle of
the
> blade for a given pitch at the given radius. c=2(pi)r, r=the
radius in
> question. pi=3.l4l4 If you know basic algebra and trig, you
can
> fig about all you would need to know. Stan
>For example: for your 12" dia , with 22" pitch, at a radius of 5",
the formula would give tan0=p/c=2pir which
=22/31.4=0.70=tan"0",therefore the angle in question ="0"= theta=35
degrees. if I did the math right. Stam
Received on Thu Mar 27 2008 - 17:16:10 CET
This archive was generated by Yannick on Sat Dec 14 2019 - 19:13:45 CET